The mass of H₂O produced from the reaction is 2.25 g
We'll begin by calculating the mass of N₂H₄ that reacted and the mass of H₂O produced from the balanced equation.
N₂H₄ + 3O₂ —> 2NO₂ + 2H₂O
Molar mass of N₂H₄ = (2×14) +(4×1) = 32 g/mol
Mass of N₂H₄ from the balanced equation = 1 × 32 = 32 g
Molar mass of H₂O = (2×1) + 16 = 18 g/mol
Mass of H₂O from the balanced equation = 2 × 18 = 36 g
SUMMARY
From the balanced equation above,
32 g of N₂H₄ reacted to produce 36 g of H₂O.
From the balanced equation above,
, 32 g of N₂H₄ reacted to produce 36 g of H₂O.
Therefore,
2 g of N₂H₄ will react to produce = (2 × 36) / 32 = 2.25 g of H₂O
Thus, the mass of H₂O produced from the reaction is 2.25 g
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