The kinetic energy of a ball with a mass of 2 kg that is rolling at a velocity of 5 m/s is 5 Joules
From the question, we are to determine the kinetic energy of the ball
From the given equation for the velocity,
[tex]v = \sqrt{\frac{2K}{m} }[/tex]
We will make K the subject of the equation
[tex]v = \sqrt{\frac{2K}{m} }[/tex]
Take the squares of both sides
[tex]v^{2} ={\frac{2K}{m} }[/tex]
Multiply both sides by m
[tex]mv^{2} ={\frac{2K}{m} } \times m[/tex]
[tex]mv^{2} =2K[/tex]
∴ [tex]K = \frac{1}{2} mv^{2}[/tex]
Now, for the kinetic energy of a ball with a mass of 2 kilograms that is rolling at a velocity of 5 meters/second
That is,
m = 2 kg
and v = 5 m/s
Putting the parameters into the equation, we get
[tex]K = \frac{1}{2} \times 2 \times 5^{2}[/tex]
K = 25 J
Hence, the kinetic energy of a ball with a mass of 2 kg that is rolling at a velocity of 5 m/s is 5 Joules
Learn more on Calculating kinetic energy here: https://brainly.com/question/25959744
Here is the complete question:
Select the correct answer from each drop-down menu. The velocity, v, in meters/second, of an object with a mass of m, in kilograms, and kinetic energy of K, in joules, is given by this equation.
[tex]v = \sqrt{\frac{2K}{m} }[/tex]
Use the equation to complete this statement. The kinetic energy of a ball with a mass of 2 kilograms that is rolling at a velocity of 5 meters/second is joules.
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