Given:
The perimeter of a rectangular building is 1200 feet.
The width of the building is 2 feet less than three times the length.
To find:
Width of the building.
Solution:
Let length of the building be x.
Then, width = 3x-2
We know that,
[tex]Perimeter=2(length +width)[/tex]
[tex]1200=2(x+3x-2)[/tex]
[tex]1200=2(4x-2)[/tex]
[tex]1200=8x-4[/tex]
Add 4 on both sides
[tex]1204=8x[/tex]
Divide both sides by 8.
[tex]\dfrac{1204}{8}=x[/tex]
[tex]150.5=x[/tex]
Now,
[tex]Width=3x-2[/tex]
[tex]Width=3(150.5)-2[/tex]
[tex]Width=451.5-2[/tex]
[tex]Width=449.5[/tex]
Therefore, the width of the building is 449.5 feet.
