Answer:
There are approximately 8.183 × 10²³ units of PbO₂ in 325 grams of PbO₂
Explanation:
The given mass of PbO₂ = 325 grams
The molar mass of PbO₂ = 239.2 g/mol
The number of moles of PbO₂ in 325 grams of PbO₂ is given by the formula for the number of moles of a chemical compound in a given sample of the compound as follows;
[tex]The \ number \ of \ moles, n = \dfrac{Mass \ of \ the \ substance}{Molar \ mass \ of \ the \ substance}[/tex]
For the given PbO₂ compound, in the question, we have;
[tex]The \ number \ of \ moles, n = \dfrac{325 \ g}{239.2 \ g/mole} \approx 1.36 \ moles[/tex]
The number of units of PbO₂ in one mole is given by the Avogadro's number as follows;
The number of units of PbO₂ per mole = 6.023 × 10²³ units
The number of units of PbO₂, [tex]U_{PbO_2}[/tex] in 1.36 mole of PbO₂ is therefore;
[tex]U_{PbO_2}[/tex] = 1.36 × 6.023 × 10²³ units ≈ 8.183 × 10²³ units of PbO₂
The number of units of PbO₂, in 1.36 mole of PbO₂ ≈ 8.183 × 10²³ units.
