Answer:
Line D
Step-by-step explanation:
Slope of a line passing through [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] is given by,
m = [tex]\frac{y_2,y_1}{x_2-x_1}[/tex]
Slope of line A passing through (-6, 3) and (0, 0)
m = [tex]\frac{3-0}{-6-0}=-\frac{1}{2}[/tex]
Negative and m < 1
Slope of line B passing through (-2, 4) and (0, 0)
m = [tex]\frac{4-0}{-2-0}=-2[/tex]
Negative and m < 1
Slope of line C passing through origin and (2, 5),
m = [tex]\frac{5-0}{2-0}[/tex] = 2.5
Positive and m > 1
Slope of line D passing through origin and (3, 2)
m = [tex]\frac{2-0}{3-0}=\frac{2}{3}[/tex]
Positive but m < 1
Therefore, Line D will be the answer.
