What is the specific heat of a substance that absorbs 1000 joules of heat when a sample of 25 g of the substance increases in temperature from 10.0C to 60.0C

Respuesta :

Answer:

1250000

Explanation:

Specific heat is mass times specific heat capacity times change in temperature to get chance in temperature minus the old temperature from the new temperature then complete equation hence 25g×1000j×(60-10)

25g×1000j×50

=1250000g/j/degree Celsius