Which one of these relationships is different than the other three? Write the equation for each line,or find the slope (one of them is different from the other3)

Answer:
Graph B is different from the others.
Equation for Graph A, C, and D is [tex] y = 5x [/tex].
Equation of Graph B is [tex] y = 5.5x [/tex]
Step-by-step explanation:
The equation of each line can be written as [tex] y = mx [/tex], where m is the slope.
Using each point given in each graph, we can find m and also an equation for each graph:
✍️Graph A Equation and slope:
Using the point given, (0.8, 4), the slope, m, can be calculated as,
[tex] m = \frac{y}{x} = \frac{4}{0.8} = 5 [/tex]
Substitute m = 5 into [tex] y = mx [/tex].
✅Equation for graph A would be [tex] y = 5x [/tex].
✍️Graph B Equation and slope:
Using the point given, (10, 55), the slope, m, can be calculated as,
[tex] m = \frac{y}{x} = \frac{55}{10} = 5.5 [/tex]
Substitute m = 5.5 into [tex] y = mx [/tex].
❌Equation for graph B would be [tex] y = 5.5x [/tex].
✍️Graph C Equation and slope:
Using the point given, (4, 20), the slope, m, can be calculated as,
[tex] m = \frac{y}{x} = \frac{20}{4} = 5 [/tex]
Substitute m = 5 into [tex] y = mx [/tex].
✅Equation for graph C would be [tex] y = 5x [/tex].
✍️Graph D Equation and slope:
Using the point given, (10, 50), the slope, m, can be calculated as,
[tex] m = \frac{y}{x} = \frac{4}{0.8} = 5 [/tex]
Substitute m = 5 into [tex] y = mx [/tex].
✅Equation for graph D would be [tex] y = 5x [/tex].
Equation for Graph A, C, and D is [tex] y = 5x [/tex].
Equation of Graph B is [tex] y = 5.5x [/tex]