Answer:
A. The balloons will increase to twice their original volume.
Explanation:
Boyle's law states that the pressure exerted on a gas is inversely proportional to the volume occupied by the gas at constant temperature. That is:
P ∝ 1/V
P = k/V
PV = k (constant)
P = pressure, V = volume.
[tex]P_1V_1=P_2V_2[/tex]
Let the initial pressure of the balloon be P, i.e. [tex]P_1=P[/tex], initial volume be V, i.e. [tex]V_1=V[/tex]. The pressure is then halved, i.e. [tex]P_2=\frac{P}{2}[/tex]
[tex]P_1V_1=P_2V_2\\\\P*V=\frac{P}{2} *V_2\\\\V_2=\frac{2*P*V}{P}\\\\V_2=2V[/tex]
Therefore the balloon volume will increase to twice their original volume.