Answer:
Equation A is factoring, x=9 and x=0
Equation B is the square root, x=3
The equation A: x² - 9 = 0 can be solved by square root method
The equation B: x² - 9x = 0 can only be solved by factoring
The given equations are:
Equation A: x² - 9x = 0
Equation B: x² - 9 = 0
The equation x² - 9 can be rewritten as:
x² - 3² = 0
This is a difference of two squares which can be further expressed as:
(x - 3)(x + 3) = 0
x - 3 = 0
x = 3
x + 3 = 0
x = -3
This shows that the equation x² - 9 = 0 has two roots x = -3 and x = 3
Also, from x² - 9 = 0
[tex]x = \pm\sqrt{9} \\\\x = \pm3[/tex]
For the equation x² - 9x = 0
This can be factored as x(x - 9) = 0
x = 0, x = 9
This is not solved by the square root method.
Therefore, the equation x² - 9 = 0 can be solved by square root method
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