Respuesta :
Answer:
1.9998 atm
Explanation:
Balance the equation and then use PV=nRT to find the variable.
The final pressure of the chamber is 2 atm.
The given parameters;
- Temperature of the gas, T = 125 ⁰C
- Number of oxygen moles = 1
- Number of hydrogen moles, = 2
- Initial pressure of the gases, P₁ = 3 atm
The balanced chemical reaction of the given elements;
[tex]O_2 \ \ + \ 2H_2 \ \ ---> \ 2H_2O[/tex]
Initial number of moles of the gases, = 1 + 2 = 3 moles
Final number of moles of the product, = 2 moles
The final pressure of the chamber is calculated as follows;
[tex]PV = nRT\\\\\frac{P}{n} = \frac{RT}{V} \\\\\frac{P_1}{n_1} = \frac{P_2}{n_2} \\\\P_2 = \frac{P_1 n_2}{n_1} \\\\P_2 = \frac{3 \times 2}{3} \\\\P_2 = 2 \ atm[/tex]
Thus, the final pressure of the chamber is 2 atm.
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