Answer:
C
Step-by-step explanation:
Distance: 8.6 miles; Bearing: 44.7 degrees East of North.
The distance of the ship which leaves port on a bearing of 20.2 degrees East of North is 8.6 miles and its bearing is 44.7 degrees East of North.
When the three sides of a triangle is known, then to find any angle, the law of cosine is used.
It can be given as,
[tex]c^2=a^2+b^2-2ab\cos C\\a^2=c^2+b^2-2ab\cos A\\b^2=a^2+c^2-2ab\cos B[/tex]
Here, a,b and c are the sides of the triangle and A,B and C are the angles of the triangle.
A ship leaves port on a bearing of 20.2 degrees East of North and travels 6.5 miles. The ship then turns due East and travels 3.8 miles.
This problem is shown in the image. The distance of ship from initial point is,
[tex]c=\sqrt{6.5^2+3.8^2-{2\times6.5\times3.8\times\cos (110.2)}}\\c\approx8.6\rm\; miles[/tex]
The measure of the angle x is,
[tex]\angle x=\cos^{-1}\dfrac{8.6^2+3.8^2-6.5^2}{2\times8.6\times3.8}\\\angle x=44.7^o[/tex]
Hence, the distance of the ship which leaves port on a bearing of 20.2 degrees East of North is 8.6 miles and its bearing is 44.7 degrees East of North.
Learn more about the law of cosine here;
https://brainly.com/question/4372174
