Step-by-step explanation:
[tex]( - 3 {x}^{2} - 9x) \div (x + 3) [/tex]
This is the original equation so you will open the brackets.
[tex] - 3 {x}^{2} - 9x \div x + 3[/tex]
The x will cross the division sign making it times x.
[tex]3 {x}^{2} - 9x \times x = 3[/tex]
So you will proceed to multiply the 9x by x making it;
[tex]3 {x}^{2} - 9 {x}^{2} = 3 [/tex]
So you will subtract 9x² from 3x² which won't be possible so it will be negative.
[tex] - 6 {x}^{2} = 3 [/tex]
Then you will square root both sides making it;
[tex] - \sqrt{6 {x}^{2} } = \sqrt{3} [/tex]
So the ² will cancel the √ leaving
-6x=√3
-6x=1.73(Divide both sides by -6)
x=0.288
That's the final answer.
