Respuesta :
Answer:
Step-by-step explanation:
Hello,
[tex]\forall x \in \mathbb{R} \\\\(f+g)(x)=f(x)+g(x)=x^2+1+5-x=x^2-x+4 \\\\(f-g)(x)=f(x)-g(x)=x^2+1-5+x=x^2+x-4[/tex]
Thanks
Answer:
c for the first one and a for the second one
Step-by-step explanation:
just did it on edg