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Radio signals travel at a rate of 3 × 10^8 meters per second. How many seconds will it take for a radio signal to travel from a satellite to the surface of the Earth if the satellite is orbiting at a height of 3.6 × 10^7 meters?

10.8 × 10^15 seconds

1.2 × 10^–1 seconds

1.08 × 10^16 seconds

8.3 seconds

Respuesta :

mariocervantes239

Answer:

b or 1.2*10⁻1

Step-by-step explanation:

10^8=one hundred million and that *3=three hundred million

10^7=ten million*3.6=36 million.

it has to be about 0.1 seconds so b

xenia168

Answer:

1.2 × [tex]10^{-1}[/tex] of a second

Step-by-step explanation:

d = vt , t = d / v

t = ( 3.6 × [tex]10^{7}[/tex] )( 3 × [tex]10^{8}[/tex] ) = (3.6 ÷ 3) × ( [tex]10^{7}[/tex] ÷ [tex]10^{8}[/tex] ) = 1.2 × [tex]10^{7 - 8}[/tex] = 0.12 of second

t = 1.2 × [tex]10^{-1}[/tex] of a second