Answer:
1/6y+1/6(y+12)- 2
Step-by-step explanation:
- Distribute [tex]\frac{1}{6}[/tex] through the parentheses : [tex]\frac{1}{6}[/tex]y + [tex]\frac{1}{6}[/tex]y + 2 - 2
- Remove the opposites and calculate ( since two opposites add up to zero remove them from the expression) : [tex]\frac{1}{6}[/tex]y + [tex]\frac{1}{6}[/tex]y
- Calculate the sum : [tex]\frac{1}{3}[/tex] y
Solution : [tex]\frac{1}{3}[/tex] y
