The tens digit is 3 and the unit digit is 8. So, the number is 38.
Important information:
Let x be the tens digit and y be the unit digit.
The tens digit is 5 less than the unit digit.
[tex]x=y-5[/tex] ...(i)
The number itself is five more than three times the sum of its digits.
[tex]10x+y=3(x+y)+5[/tex]
[tex]10x+y-3x-3y=5[/tex]
[tex]7x-2y=5[/tex] ...(ii)
Using (i) and (ii), we get
[tex]7(y-5)-2y=5[/tex]
[tex]7y-35-2y=5[/tex]
[tex]5y=40[/tex]
[tex]y=8[/tex]
Substitute this value in (i).
[tex]x=8-5[/tex]
[tex]x=3[/tex]
Therefore, the number is 38.
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