The number of ways of distinct orders can be seated if two people of the same party are considered identical should be 5,544 ways.
[tex]= \frac{12!}{1!5!6!} \\\\= \frac{12\times11\times10\times9\times8\times7\times6!}{6!\times5\times4\times3\times2\times1}\\\\= \frac{12\times11\times10\times9\times8\times7}{5\times4\times3\times2\times1}\\\\= 5,544[/tex]
= 5,544 ways
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