a. Jason's mother to catch him after time of 5minutes.
b. Jason biked for distance of 3miles when his mother catches him.
c. Mother has to drive with speed of 60mph to catch him at the school door, if Jason's school is 2.5 miles from his apartment.
" Speed is defined as the total distance travelled per unit time."
Formula used
[tex]Speed = \frac{total distance travelled}{total time taken}[/tex]
According to the question,
Speed of Jason bike = 12mph
1hour = 12miles
60minutes = 12miles
1minutes = [tex]\frac{12}{60}[/tex] miles
Speed of Jason's mother bike = 36mph
Time after mother found the homework = 10 minutes
After 10 minutes
Jason is at distance = [tex]\frac{12}{60} (10)[/tex]
=2miles
After 15 minutes = [tex]\frac{12}{60} (15)[/tex]
= 3miles
To cover three miles mother has to drive for
1hour = 36miles
60minutes = 36miles
1miles = [tex]\frac{60}{36}[/tex] minutes
3miles = [tex]\frac{60}{36} (3)[/tex]
= 5minutes
If Jason's school is 2.5 miles from his apartment,
Time taken by Jason to reach school door = [tex]\frac{2.5}{12.5} (60)[/tex] minutes
= 12.5 minutes
Time in which mother has to cover distance of 2.5miles
= [tex](12.5-10)[/tex]minutes
= 2.5minutes
Substitute the value in the formula we get,
Speed of mother's bike = [tex]\frac{2.5}{2.5} (60)[/tex] mph
= 60mph
Hence,
a. Jason's mother to catch him after time of 5minutes.
b. Jason biked for distance of 3miles when his mother catches him.
c. Mother has to drive with speed of 60mph to catch him at the school door, if Jason's school is 2.5 miles from his apartment.
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