# 6
Write an equation in slope-intercept
form to represent the line
perpendicular to 2x + 10y = 3 passing
through the point (2, 3).
O y = 1/5x+3/10
O y = 5x + 13
y = 5x - 7
O y = -1/5x + 17/5

We can make an equation for the perpendicular line by swapping the x- and y-coefficients, negating one of them. Then we can use that form with the given point to see what the constant is.

10x -2y = ...

Removing a common factor of 2 gives ...

5x -y = 5(2) -(3) = 7 . . . . using (x, y) = (2, 3), we can find the constant

Solving for y, we get ...

5x -7 = y . . . add y-7

y = 5x -7 . . . write in the desired form

# 6 Write an equation in slope-intercept form to represent the line perpendicular to 2x + 10y = 3 passing through the point (2, 3). O y = 1/5x+3/10 O y = 5x + 13 y = 5x - 7 O y = -1/5x + 17/5

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# 6
Write an equation in slope-intercept
form to represent the line
perpendicular to 2x + 10y = 3 passing
through the point (2, 3).
O y = 1/5x+3/10
O y = 5x + 13
y = 5x - 7
O y = -1/5x + 17/5