Step 2: Evaluating trends of data

Because you want to prepare and serve the healthiest food possible, you monitor the fat and calorie content of items on your menu. Some of the menu items are included in the graph below.

a) Your business partner describes this as a high positive correlation. Is your partner correct? Why or why not? (2 points)

b) Using the drawing tools, draw a trend line (line of best fit) on the graph above. (2 points)

c) Judge the closeness of your trend line to the data points. Do you notice a relationship between the data points? (2 points)

d) Is the trend line linear? If so, write a linear equation that represents the trend line. Show your work. (3 points)
------ ill give you brainliest if u get this answer correct. If u put in a random answer = reported

This is so, because as the fat content increases, the calorie content also increases, and the data points are very close to the trend line

(b) The trend line

See attachment

(c) The relationship between the data points

From the attached image, we can see that the data points are very close to the trend line.

This means that: there is a relationship between the trend line and the data points.

And the relationship is: the fat content increases with the calorie content

(d) Linear equation

The trend line is linear, because it is represented by a straight line.

From the graph, we have the following points

[tex]\mathbf{(x,y) = (8,500)(2,200)}[/tex]

Calculate the slope as follows:

[tex]\mathbf{m = \frac{y_2 - y_1}{x_2 - x_1}}[/tex]

So, we have:

[tex]\mathbf{m = \frac{200-500}{2-8}}[/tex]

[tex]\mathbf{m = \frac{-300}{-6}}[/tex]

[tex]\mathbf{m = 50}[/tex]

The equation is then calculated as:

[tex]\mathbf{y = m(x -x_1) + y_1}[/tex]

So, we have:

[tex]\mathbf{y = 50(x -8) + 500}[/tex]

[tex]\mathbf{y = 50x -400 + 500}[/tex]

[tex]\mathbf{y = 50x +100}[/tex]

Hence, the linear equation is: [tex]\mathbf{y = 50x +100}[/tex]