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. A driver travels 4.25 km. in two minutes. If the driver’s initial velocity is 20m/s, what is the acceleration?
With an average acceleration of -1.2m/s2, how long will it

Respuesta :

Answer:

32.9166667 m / s^2

Explanation:

s = 4.25km (1000m / 1km)

= 4250m

u = 20m/s

delta T = 20min (60sec / 1min)

= 1200s

Use formula s = ut + (1/2)at^2

4250m = 20m/s * 1200s + (1/2)a*1200s^2

Rearrange it to find a

a = (s-ut)  / (1/2 * t^2)

a = (4250m - 20m/s*1200s) / (1/2 * 1200s^2)

a = -32.9166667 m / s^2

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