Q4: Write the equation in slope-intercept form of the line that is perpendicular to
the graph of each equation and passes through the given point.
y = -5x + 1; (2, -1)

Respuesta :

Answer:

5y  = x + 11

Step-by-step explanation:

Given parameters:

  Equation of the line ;

           y  = -5x + 1

  Coordinates = (2, -1)

Find the equation of a line perpendicular;

Solution:

A line perpendicular to  y  = -5x + 1  will have slope that is a negative inverse of the given one.

Equation of a straight line is expressed as;

           y  = mx + c

y and x are the coordinates

m is the slope

c is the y-intercept

        So, the slope of the new line perpendicular is [tex]\frac{1}{5}[/tex] ;

Now let us find the y-intercept of the new line;

   x = -1 and y = 2

      2  = [tex]\frac{1}{5}[/tex] x (-1) + c

           c  = 2 + [tex]\frac{1}{5}[/tex]   = [tex]\frac{11}{5}[/tex]  

The equation of the new line is;

          y  =  [tex]\frac{1}{5}[/tex]x +  [tex]\frac{11}{5}[/tex]  

or multiply through by 5;

        5y  = x + 11