Respuesta :
Answer:
-114kJ mol-1
Explanation:
Definition of the enthalpy change of neutralization: the energy released with the formation of 1 mole of water when neutralization takes place between an acid and a base.
Since both reactions yield the same number of moles of water, the answer should be -114kJ mol-1.
The statement for the enthalpy change of reaction 2 is "-114 kJ"
What is enthalpy change?
The change in enthalpy (ΔH) is a quantity of heat of a system. The enthalpy change is the amount of heat that enters or exits a system during a reaction.
One equivalent of hydrogen ions is neutralised with one equivalent of hydroxide ions in the reaction 1,
NaOH(aq) + HCl(aq) → NaCl(aq) + H2O(l)
The change in enthalpy is given as -114 kJ.
Two equivalents of hydrogen ions are neutralised with two equivalents of hydroxide ions in the reaction 2,
Ba(OH)2 + H2SO4 (aq) → BaSO4 (s) + 2H2O (l)
But, that primary ionic reaction is same for both the reaction in which hydrogen ion combines with hydroxide ion to generate a water molecule. So, the enthalpy change of reaction 1 would be exactly same as for reaction 2.
The neutralization enthalpy comes out to be -114 kJ.
Hence the correct answer is -114 kJ.
Learn more about enthalpy change here
https://brainly.com/question/4526346
#SPJ2
