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What is the boiling point in °C) of a 0.527 m
aqueous solution of LiBr?
Enter your rounded answer with
3 decimal places.

Respuesta :

jahshauushshaha
Answer:

100.54 °C


Explanation:

Supposing complete ionization:
LiBr → Li{+} + Br{-] [two ions]

• (0.527 m LiBr) x (2 mol ions / 1 mol LiBr) = 1.054 m ions

• (0.512 °C/m) x (1.054 m) = 0.540 °C change

• 100.00°C + 0.540 °C = 100.54 °C
xenapin808

Answer:

100.54

Explanation:

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