what is the solution to the system of equations?

Answer:
No solution
Step-by-step explanation:
[tex]-3x-4y-3z=-7\\2x-6y+2z=3\\5x-2y+5z=9\\\\[/tex]
Lets consider the equation 2.
Here we multiply the LHS and RHS with (-1).
[tex]-3x-4y-3z=-7\\-(2x-6y+2z)=-3\\5x-2y+5z=9\\\\[/tex]
Hence,
[tex]-3x-4y-3z=-7\\-2x+6y-2z=-3\\5x-2y+5z=9\\\\[/tex]
When we add the equations we get,
[tex]0x+0y+0z=-10+9\\Hence,\\0=-1[/tex]
As 0 doesn't equal to -1, answer is d) No solution