Answer:
No
Why he is not correct is because the y-intercept is the coordinate of the point where the graph meets or crosses the y-axis, which is equivalent to a point on the graph where the x-coordinate value reduces to zero, or to put it in a mathematical form x = 0
Step-by-step explanation:
From the given data, we have;
x [tex]{}[/tex] y
2 [tex]{}[/tex] -2
4 [tex]{}[/tex] 0
6 [tex]{}[/tex] 2
8 [tex]{}[/tex] 6
The given data is linear because it has a constant first (common) difference of 2
The general form of the straight line equation is y = m·x + c
Where;
m = The slope
c = The y-intercept
[tex]Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]
The slope of the graph of the data from any two points, (x₁, y₁) = (4, 0) and (x₂, y₂) = (4, 0)) is m = (2 - 0)/(6 - 4) = 1
The equation representing the data in point and slope form is therefore;
y - 4 = 1 × (x - 0)
Which gives;
y = x + 4
Therefore, the y-intercept = 4.
