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What is the total amount of heat required to completely vaporize a 100.0 g of
water at its normal boiling point?

Work too pls !!

Respuesta :

ardni313

The total amount of heat : 225.704 kJ

Further explanation

Heat of vaporization(ΔH vap) : heat needed to vaporize 1 mole of water , units : kJ/mol

For water at boiling point (100 °C) : ΔH vap = 40.66 kj/mol

mole of 100 g water :

[tex]\tt \dfrac{100}{18.015}=5.551[/tex]

so total Heat :

[tex]\tt 40.66\times 5.551=225.704~kJ[/tex]

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