Peter works as a delivery person for a bike shipping company. The graph shows a linear model for his delivery times on different days. Peter’s Deliveries What is the equation of the line, first written in point-slope form, and then written in slope-intercept form? Show how you determined the equation. Based on the linear model, predict how long it initially took Peter to deliver his packages (y-intercept). Approximately how much did his delivery time decrease per day (slope)? Complete sentences.I need this done before Monday, please!

Peter works as a delivery person for a bike shipping company The graph shows a linear model for his delivery times on different days Peters Deliveries What is t class=

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Answer/Step-by-step explanation:

✍️The equation of the line in point-slope form:

The equation is given as [tex] y - b = m(x - a) [/tex], where,

(a, b) = a point on the line.

[tex] slope (m) = \frac{y_2 - y_1}{x_2 - x_1} [/tex]

Let's find the slope (m) of the line, housing (3, 21) and (6, 12):

[tex] slope (m) = \frac{y_2 - y_1}{x_2 - x_1} = \frac{12 - 21}{6 - 3} = \frac{-9}{3} = -3 [/tex]

Substitute a = 3 and b = 21, m = -3 into [tex] y - b = m(x - a) [/tex].

Thus, the point-slope equation would be:

✅[tex] y - 21 = -3(x - 3) [/tex]

✍️The equation of the line in slope-intercept form:

Rewrite [tex] y - 21 = -3(x - 3) [/tex], so that y is made the subject of the formula.

[tex] y - 21 = -3x + 9 [/tex]

Add 21 to both sides

[tex] y = -3x + 9 + 21 [/tex]

[tex] y = -3x + 30 [/tex]

✅The slope-intercept equation of the line is [tex] y = -3x + 30 [/tex]

Where,

-3 = how much did his delivery time decrease per day (slope)

30 = how long it initially took Peter to deliver his packages (y-intercept)