HELP ME PLEASE!
Complete the work to find the equation of a line that passes through point (–5, –3) and is parallel to line y – 3x = –7. Step 1: Write the equation of the given line in slope intercept form: y = 3x – 7. Step 2: Determine the slope of the parallel line: m = 3. Step 3: Substitute the slope and given point into y = mx + b to find the y-intercept of the new line. –3 = 3 (–5 ) + b 3 = –15 + b b = 12 Step 4: Write the equation of the line parallel to 3x – y = 7 that passes through point (–5, –3).

Respuesta :

Answer:

Y=3x+12 (its the first option)

Step-by-step explanation:

I did the assignment.

The equation of the line parallel to (3x - y = 7) passes through the point (-5, -3) is y = 3x + 2 and this can be determined by using the one-point slope form.

Given :

The line passes through the point (-5, -3) and is parallel to the line (y - 3x = -7).

The following steps can be used in order to determine the equation of a line that passes through the point (-5, -3) and is parallel to the line (y - 3x = -7):

Step 1 - The one-point form of a line is used in order to determine the equation of a line that passes through the point (-5, -3) and is parallel to the line (y - 3x = -7).

Step 2 - The one-point form is given below:

[tex](y-y_1) = m (x-x_1)[/tex]

Step 3 - According to the given data, the line is parallel to the line (y = 3x - 7). So, the slope of the line is 3.

Step 4 - Now, substitute the values of slope and the point in the above expression.

[tex](y+3) = 3 (x+5)[/tex]

y = 3x + 2

For more information, refer to the link given below:

https://brainly.com/question/19300779