1. Priya jogs at a constant speed. The relationship between her distance and time is
shown on the graph. Diego bikes at a constant speed twice as fast as Priya.
Sketch a graph showing the relationship between Diego's distance and time.

1 Priya jogs at a constant speed The relationship between her distance and time is shown on the graph Diego bikes at a constant speed twice as fast as Priya Ske class=

Respuesta :

Answer:

Step-by-step explanation:

Relationship between distance the distance and time for Priya has been given  in the graph.

Therefore, slope of the line on the graph will represent the speed of jog of Priya.

Slope = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]

Where [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] are the points lying on the line.

Since, (0, 0) and (0.4, 2) are lying on the line.

Therefore, slope or speed of the line will be,

Speed = [tex]\frac{2-0}{0.4-0}[/tex]

           = 5

Now Diego bikes at a speed twice as fast as Priya,

So Diego's speed = 5×2 = 10 mile per hour

Therefore, slope of the line for Diego on graph will be,

m = 10

Line passing through origin and slope = 10 will be,

y = 10x

Points representing Diego's speed will be,

x      0      0.1       0.2     0.3     0.4     0.5

y      0        1          2        3        4         5

Now we can graph these points to get the line.

Ver imagen eudora

Relationship between distance the distance and time for Priya has been given  in the graph.

Therefore, slope of the line on the graph will represent the speed of jog of Priya.

Slope =

Where  and  are the points lying on the line.

Since, (0, 0) and (0.4, 2) are lying on the line.

Therefore, slope or speed of the line will be,

Speed =

          = 5

Now Diego bikes at a speed twice as fast as Priya,

So Diego's speed = 5×2 = 10 mile per hour

Therefore, slope of the line for Diego on graph will be,

m = 10

Line passing through origin and slope = 10 will be,

y = 10x

Points representing Diego's speed will be,

x      0      0.1       0.2     0.3     0.4     0.5

y      0        1          2        3        4         5

Now we can graph these points to get the line.