Respuesta :

meghanbf

The average rate of change over an interval is the same as the slope between those two values.  The formulate for slope is:

[tex]m=\frac{y_{2}-y_{1} }{x_{2}-x_{1}}[/tex]

You are given the x values: x2=3 and x1=-9.  Plug in these x values to g(x) find the y values:

g(3)=3^2+5(3)-2=9+15-2=22

g(-9)=(-9)^2+5(-9)-2=81-45-2=34

Now, you can solve for m:

m=(22-34)/(3--9)

m=-12/12

m=1

Hope this helps!!

abidemiokin

the  average rate of change of the function over the interval -9 ≤ x ≤ 3​ is -1

The average rate is the change of expression with respect to time.

Given the expression g(x)=x^2+5x-2 within the interval -9 ≤ x ≤ 3​

At the lower interval x = -9

g(-9) = (-9)²+5(-9)-2

g(-9)= 81-45-2

g(-9) = 34

At the upper interval x = 3

g(3) = (3)²+5(3)-2

g(3)= 9+15-2

g(3) = 22

The average change of the function will be expressed as:

[tex]\frac{\triangle y}{\triangle x} =\dfrac{g(b)-g(a)}{b-a}\\ \frac{\triangle y}{\triangle x} =\dfrac{g(3)-g(-9)}{3-(-9)}\\\frac{\triangle y}{\triangle x} =\dfrac{22-34}{12}\\\\\frac{\triangle y}{\triangle x} =\dfrac{-12}{12} \\\frac{\triangle y}{\triangle x} =-1[/tex]

Hence the  average rate of change of the function over the interval -9 ≤ x ≤ 3​ is -1

Learn more here: https://brainly.com/question/7590674

Otras preguntas