Respuesta :

The empirical formula : C₁₂H₁₇N₂O₄P

Further explanation  

The empirical formula is the smallest comparison of atoms of compound =mole ratio of the components

The principle of determining empirical formula

  • Determine the mass ratio of the constituent elements of the compound.  
  • Determine the mole ratio by by dividing the percentage by the atomic mass

  • C

[tex]\tt \dfrac{50.7}{12}=4.225[/tex]

  • H

[tex]\tt \dfrac{6.03}{1}=6.03[/tex]

  • N

[tex]\tt \dfrac{9.86}{14}=0.704[/tex]

  • O

[tex]\tt \dfrac{22.51}{16}=1.407[/tex]

  • P

[tex]\tt \dfrac{10.9}{31}=0.352[/tex]

Divide by the smallest mole ratio(0.352)

C : H : N : O : P

[tex]\tt C\rightarrow \dfrac{4.225}{0.352}=12[/tex]

[tex]\tt H\rightarrow \dfrac{6.03}{0.352}=17[/tex]

[tex]\tt N\rightarrow \dfrac{0.704}{0.352}=2[/tex]

[tex]\tt O\rightarrow \dfrac{1.407}{0.352}=4[/tex]

[tex]\tt P\rightarrow \dfrac{0.352}{0.352}=1[/tex]