Use the discriminant to determine how many and what kind of solutions the quadratic equation 3x^2 + 4x = - 5 has.

A. one real solution

B. two complex (nonreal) solutions

C. no real or complex solutions

D. two real solutions

Pls help!

Respuesta :

Answer:

C.

Step-by-step explanation:

The quadratic equation has two complex (nonreal) solutions option (B) is correct.

What is a quadratic equation?

Any equation of the form [tex]\rm ax^2+bx+c=0[/tex]  where x is variable and a, b, and c are any real numbers where a ≠ 0 is called a quadratic equation.

As we know, the formula for the roots of the quadratic equation is given by:

[tex]\rm x = \dfrac{-b \pm\sqrt{b^2-4ac}}{2a}[/tex]

We have a quadratic equation:

3x² + 4x = - 5

or

3x² + 4x + 5 = 0

D = b² - 4ac

b = 4, a = 3, c = 5

D = (4)² - 4(3)(5)

D = 16 - 60

D= -44

D < 0

Two complexes (nonreal) solutions

Thus, the quadratic equation has two complexes (nonreal) solutions option (B) is correct.

Learn more about quadratic equations here:

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