Respuesta :
Answer:
Explanation:
2Al(s) + 3 I₂(s) → 2 Al⁺³ + 6 I⁻
Aluminium is oxidised and iodine is reduced .
so cell potential = Ereduction - Eoxidation
Al⁺³ + 3e = Al - 1.66 V
I₂ + 2 e = 2 I⁻ 0.54 V
= .54 - ( - 1.66 )
= 1.66 + .54
= 2.2 V
The overall standard cell potential for the given cell that employs the overall cell reaction is; E°_cell = 2.20 V
We are given the cell reaction;
2Al (s) + 3I₂ (s) → 2Al⁺³ + 6I⁻
We are given reduction potential as;
Al⁺³(aq) + 3e⁻ → Al(s) ;E°_red = -1.66 V
However, the standard reduction potential for the reverse of the oxidation reaction is;
Al → Al⁺³(aq) + 3e⁻ ;E°_ox = 1.66 V
We are also given;
I₂ + 2e⁻ = 2I⁻ ;E°_red = 0.54 V
To get overall standard cell potential, we will add the cell potentials to get;
E°_cell = E°_ox + E°_red
E°_cell = 1.66 + 0.54
E°_cell = 2.20 V
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