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A force act on a bicycle for 2.4 sec, and changes its momentum from 20 kg m/s in the x positive direction to 40 Kg m/s in the Positive x direction, what is the magnitude of the force?

A. -10 N
B. 137.5 N
C. 8.33 N
D. -137.5 N

Respuesta :

ThulithaInduwara

Answer:

Increased momentum =40-20=20

F=P/T=20/2.4=8.33N

Explanation:

F=(force)

P=(momentum)

T=(time)
Answer: B 137.5
Explanation

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