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1. An organic compound is found to contain the
following constituents :
C = 33.8%. H = 4.7%., N - 13:2%, Cl= 33.4%
and rest is Oxygen. Determine its empirical mass?
​

Respuesta :

ardni313

Emperical formula

C₃H₅NClO

Further explanation  

The empirical formula is the smallest comparison of atoms of compound =mole ratio of the components

The principle of determining empirical formula

  • Determine the mass ratio of the constituent elements of the compound.  
  • Determine the mole ratio by by dividing the percentage by the atomic mass

mole ratio :

  • C

[tex]\tt \dfrac{33.8}{12}=2.82[/tex]

  • H

[tex]\tt \dfrac{4.7}{1}=4.7[/tex]

  • N

[tex]\tt \dfrac{13.2}{12}=1.1[/tex]

  • Cl

[tex]\tt \dfrac{33.4}{35.5}=0.94[/tex]

  • O

[tex]\tt \dfrac{14.9}{16}=0.93[/tex]

we divide by the smallest mole ratio (0.93)

C : H : N : Cl : O =

[tex]\tt \dfrac{2.82}{0.93}\div \dfrac{4.7}{0.93}\div \dfrac{1.1}{0.93}\div \dfrac{0.94}{0.93}\div \dfrac{0.93}{0.93}\\\\3\div 5\div 1\div 1\div 1[/tex]

Emperical Formula :

[tex]\tt C_3H_5NClO[/tex]

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