f(x)=-2x^2+14/x^2-49 which statement describes the behavior of the graph of the function shown at the vertical asymptotes?

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Answer:

Option 3 :

x → 7+, y → –[infinity]

Step-by-step explanation:

f(x) = (-2x² + 14)/(x² - 49)

x² - 49 = (x + 7)(x - 7)

Hence f(x) goes to infinity at x = - 7 or 7

x < - 7 = (-ve)(-ve) = + ve

=> x → –7–

Here, x² - 49 is + ve

-7 < x < 7 = (+ve)(-ve) = - ve

=> x → –7+ or x → 7– .

here, x² - 49 is - ve

x > 7 = (+ve)(+ve) = + ve

=> x → 7+

Here, x² - 49 is + ve

So (-2x² + 14) is - ve for all [ x → –7– , x → –7+ , x → 7– , x → 7+ ]

As,

-2(-7)² + 14 = -84 and -2(+7)² + 14 = -84

x → –7– = (-ve)/(+ve)

=> y → -[infinity].

x → –7+ or x → 7– = (-ve)/(-ve)

=> y → [infinity]

x → 7+ = (-ve)/(+ve)

=> y → -[infinity].

x → 7+, y → –[infinity]. is the correct option

The statement (C) as x approaches 7 from the left, y approaches -∞ describe the behavior of the graph of the function.

What is a function?

It is defined as a spceial type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

We have a rational function:

[tex]\rm f(x) =\dfrac{-2x^2+14}{x^2-49}[/tex]

x² - 49 cannot be zero:

x² - 49 ≠ 0

x ≠ 7, x ≠  -7

From the graph, as x approaches 7 from the left, y approaches -∞

Thus, the statement (C) as x approaches 7 from the left, y approaches -∞ describe the behavior of the graph of the function.

Learn more about the function here:

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