f(x)=-2x^2+14/x^2-49 which statement describes the behavior of the graph of the function shown at the vertical asymptotes?

Answer:
Option 3 :
x → 7+, y → –[infinity]
Step-by-step explanation:
f(x) = (-2x² + 14)/(x² - 49)
x² - 49 = (x + 7)(x - 7)
Hence f(x) goes to infinity at x = - 7 or 7
x < - 7 = (-ve)(-ve) = + ve
=> x → –7–
Here, x² - 49 is + ve
-7 < x < 7 = (+ve)(-ve) = - ve
=> x → –7+ or x → 7– .
here, x² - 49 is - ve
x > 7 = (+ve)(+ve) = + ve
=> x → 7+
Here, x² - 49 is + ve
So (-2x² + 14) is - ve for all [ x → –7– , x → –7+ , x → 7– , x → 7+ ]
As,
-2(-7)² + 14 = -84 and -2(+7)² + 14 = -84
x → –7– = (-ve)/(+ve)
=> y → -[infinity].
x → –7+ or x → 7– = (-ve)/(-ve)
=> y → [infinity]
x → 7+ = (-ve)/(+ve)
=> y → -[infinity].
x → 7+, y → –[infinity]. is the correct option
The statement (C) as x approaches 7 from the left, y approaches -∞ describe the behavior of the graph of the function.
It is defined as a spceial type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.
We have a rational function:
[tex]\rm f(x) =\dfrac{-2x^2+14}{x^2-49}[/tex]
x² - 49 cannot be zero:
x² - 49 ≠ 0
x ≠ 7, x ≠ -7
From the graph, as x approaches 7 from the left, y approaches -∞
Thus, the statement (C) as x approaches 7 from the left, y approaches -∞ describe the behavior of the graph of the function.
Learn more about the function here:
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