Answer:
4x
Step-by-step explanation:
Given
[tex]\frac{\frac{2x^3}{3y} }{\frac{x^2}{6y} }[/tex]
= [tex]\frac{2x^3}{3y}[/tex] ÷ [tex]\frac{x^2}{6y}[/tex]
Leave the first fraction, change division to multiplication, turn the second fraction upside down, that is
[tex]\frac{2x^3}{3y}[/tex] × [tex]\frac{6y}{x^2}[/tex]
Cancel 3y and 6y by 3y and 2x³ and x² by x²
= [tex]\frac{2x}{1}[/tex] × [tex]\frac{2}{1}[/tex]
= 2x × 2
= 4x
