Answer:
y = [tex]-\frac{1}{2}[/tex]x + 12
Step-by-step explanation:
Given expressions:
Coordinates = (4,10)
Equation of the line; 6x - 3y = 5
Unknown:
Equation of the line perpendicular = ?
Solution:
A line perpendicular to the given one will have a negative inverse slope.
Equation of any given line is expressed as:
y = mx + c
y and x are the coordinates
m is the slope
c is the intercept
Now; re-write 6x-3y = 5 in the form y= mx + c and find the slope;
6x - 3y = 5
-3y = 5- 6x
y = [tex]-\frac{5}{3}[/tex] + 2x
The slope of a perpendicular line will be [tex]-\frac{1}{2}[/tex]
Also, let us find the y-intercept, c;
y = mx + c
10 = [tex]-\frac{1}{2}[/tex] x 4 + c
10 = -2 + c
c = 12
The equation of the new line is ;
y = [tex]-\frac{1}{2}[/tex]x + 12
