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[tex]4z + 2 = 10z - 1[/tex]
Add sides 1
[tex]4z + 2 + 1 = 10z - 1 + 1[/tex]
[tex]4z + 3 = 10z[/tex]
Subtract sides 4z
[tex] - 4z + 4z + 3 = - 4z + 10z[/tex]
[tex]3 = 6z[/tex]
[tex]6z = 3[/tex]
Divide sides by 6
[tex] \frac{6z}{6} = \frac{3}{6} \\ [/tex]
[tex]z = \frac{1}{2} \\ [/tex]
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[tex]3y = y + 3[/tex]
Subtract sides y
[tex] - y + 3y = - y + y + 3[/tex]
[tex]2y = 3[/tex]
Divide sides by 2
[tex] \frac{2y}{2} = \frac{3}{2} \\ [/tex]
[tex]y = \frac{3}{2} \\ [/tex]
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Thus the correct answer is :
[tex]a) \: y = \frac{3}{2} \: , \: z = \frac{1}{2} \\ [/tex]
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