Answer:
i. - 3a² + 2ab + b²
ii. 2c² + - 2cd + - 4d²
Step-by-step explanation:
i. First things first, you remove the parenthesis in both expressions to look like this:
a² − 3ab + 2b² - 4a² + 5ab − b²
Next, you add like terms.
(a² + - 4a²) + (- 3ab² + 5ab) + (2b² + - b²)
After adding these like terms, your answer would be:
- 3a² + 2ab + b²
ii. This one is pretty simply. But first, lets simplify by first removing the parenthesis to look like this:
c² - 6d² + c² - 2cd + 2d²
Then, combine like terms
(c² + c²) + (- 2cd) + (-6cd² + 2d²)
After that, your sum would be:
2c² + - 2cd + - 4d²
Hope this helps!
Answer:
see explanation
Step-by-step explanation:
i
(a² - 3ab + 2b²) + (- 4a² + 5ab - b²) ← remove parenthesis
= a² - 3ab + 2b² - 4a² + 5ab - b² ← collect like terms
= - 3a² + 2ab + b²
----------------------------------
ii
(c² - 6d²) + (c² - 2cd + 2d²) ← remove parenthesis
= c² - 6d² + c² - 2cd + 2d² ← collect like terms
= 2c² - 2cd - 4d²
