Answer:
y = - 3x + 5
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Given
3x + y + 2 = 0 ( subtract 3x + 2 from both sides )
y = - 3x - 2 ← in slope- intercept form
with slope m = - 3
Parallel lines have equal slopes, thus
y = - 3x + c ← is the partial equation
To find c substitute (3, - 4) into the partial equation
- 4 = - 9 + c ⇒ c = - 4 + 9 = 5
y = - 3x + 5 ← equation of line in form y = mx + c
The equation of line which parallel to given line is, [tex]y=3x-8[/tex]
The equation of line in slope intercept form is,
[tex]y=mx+c[/tex]
Where m is slope of line and c is y-intercept.
Equation of line given that,
[tex]y=3x+4[/tex]
So that, slope of line is [tex]3[/tex]
We have to find the equation of the line that passes through (4,4) and is parallel to given lines.
Since, slope of all parallel lines are same.
Equation of required line is,
[tex]y=3x+c[/tex]
Substitute point (4,4) in above line.
[tex]4=12+c\\\\c=4-12=-8[/tex]
So that, equation of line become,
[tex]y=3x-8[/tex]
Learn more about the equation of line here:
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