Answer:
[tex]use \: the \: following \: ponts \: to \: graph \\ \: the \: equation \to \\ \underline{\boxed{( - 1, \: - 9)...... \boxed{is \: the \: first \: point}}} \\ \underline{\boxed{( 1, \: 0)...... \boxed{is \: the \: second \: point}}} \\ \underline{\boxed{(2, \: 4)...... \boxed{is \: the \: third \: point}}} [/tex]
Step-by-step explanation:
[tex]when \: \boxed{f(x) = 3x - 5} : \: if \: \boxed{x \leqslant - 1} \\then \to \: \boxed{x = - 1} \\ f(x) = 3( - 1) - 5 \\ f(x) = - 4 - 5 \\ f(x) = - 9 \: ......... \: hence \to \\ \underline{\boxed{( - 1, \: - 9)...... \boxed{is \: the \: first \: point}}} \\. \\ . \\ . \\ when \: \boxed{f(x) = - 2x + 3} : \: if \: \boxed{ - 1 < x < 4} \\then \to \: \boxed{x = 1} \\ f(x) = - 2( 1) + 3 \\ f(x) = - 3 + 3 \\ f(x) = 0 \: ......... \: hence \to \\ \underline{\boxed{( 1, \: 0)...... \boxed{is \: the \: second \: point}}} \\ . \\ . \\ . \\ when \: \boxed{f(x) = 2 } : \: if \: \boxed{ \geqslant 4} \\then \to \: \boxed{x = 4} \\ f(x) = 2 \: ......... \: hence \to \\ \underline{\boxed{(2, \: 4)...... \boxed{is \: the \: third \: point}}} [/tex]
