What is mZDAR in circle A?
R
B
340
D
B
A
A 56°
B 340
C 68°
D 170

Answer:
68°
Step-by-step explanation:
Since, angle subtended on the circumference of the circle is half angle subtended on the center of the circle.
[tex] \therefore m\angle DBR = \frac{1}{2} \times m\angle DAR\\\\
\therefore 34\degree = \frac{1}{2} \times m\angle DAR\\\\
\therefore 34\degree \times 2= m\angle DAR\\\\
\therefore 68\degree = m\angle DAR\\\\
\therefore m\angle DAR=68\degree[/tex]