[tex]y=mx+b[/tex]
First, we find the slope.
[tex]m=\frac{y_2-y_1}{x_2-x_1} \\m=\frac{3-1}{4+6} \\m=\frac{2}{10}\\m=\frac{1}{5}[/tex]
Second, we know the slope. Substitute any ordered pairs that are given in the equation.
[tex]y=mx+b\\y=\frac{1}{5}x+b\\[/tex]
I'll use the ordered pairs (4,3) as I substitute x = 4 and y = 3.
[tex]3=\frac{1}{5}(4)+b\\3=\frac{4}{5}+b\\15=4+5b\\15-4=5b\\11=5b\\\frac{11}{5}=b[/tex]
Therefore, the equation is [tex]y=\frac{1}{5}x+\frac{11}{5}[/tex]