13. In California’s gold rush, some towns grew exponentially. If a certain town started with 45 people and had 360 people 15 months later, what is the growth rate? (r can also be per month instead of per year)

Respuesta :

Answer:

The growth rate of the town is approximately 0.212 per month.

Explanation:

The exponential model is defined by the following formula:

[tex]n = n_{o}\cdot e^{r\cdot t}[/tex] (1)

Where:

[tex]n_{o}[/tex] - Initial population, dimensionless.

[tex]r[/tex] - Growth rate, measured in [tex]\frac{1}{mo}[/tex].

[tex]t[/tex] - Time, measured in months.

[tex]n[/tex] - Current population, dimensionless.

From (1), we clear the growth rate as follows:

[tex]\frac{n}{n_{o}} = e^{r\cdot t}[/tex]

[tex]r = \frac{1}{t}\cdot \ln \frac{n}{n_{o}}[/tex] (2)

If we know that [tex]n_{o} = 45[/tex], [tex]n = 360[/tex] and [tex]t = 15\,mo[/tex], then the growth rate is:

[tex]r = \left(\frac{1}{15\,mo}\right)\cdot \ln \frac{360}{15}[/tex]

[tex]r \approx 0.212\,\frac{1}{mo}[/tex]

The growth rate of the town is approximately 0.212 per month.

fichoh

Using the exponential function, the growth rate experienced during the California's gold rush is [tex] 13.86% [/tex]

The exponential function :

  • [tex] A = A_{0}e^{rt} [/tex]

  • [tex]A_{0} = initial \: population = 45 \: people [/tex]

  • [tex] r = growth rate [/tex]

  • [tex] t = time = 15 \: months [/tex]

Substituting the values into the equation :

[tex] 360 = 45e^{15r} [/tex]

Divide both sides by 45

[tex] \frac{360}{45}= e^{15r} [/tex]

[tex] 8 = e^{15r} [/tex]

Take the In of both sides

[tex] 2.07944 = 15r [/tex]

[tex] r = \frac{2.07944}{15} = 0.13863 [/tex]

Hence, the monthly growth rate is 13.86%

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