The resulting temperature : 546.91 K = 273.91 °C
Boyle's law and Gay Lussac's law
[tex]\tt \dfrac{P_1.V_1}{T_1}=\dfrac{P_2.V_2}{T_2}[/tex]
P1 = initial gas pressure (N/m² or Pa)
V1 = initial gas volume (m³)
P2 = final gas pressure
V2 = the final volume of gas
T1 = initial gas temperature (K)
T2 = final gas temperature
P₁=10 atm
V₁=2.36 L
T₁=25+273=298 K
P₂=5.56 atm
V₂=7.79 L
[tex]\tt T_2=\dfrac{P_2.V_2.T_1}{P_1.V_1}\\\\T_2=\dfrac{5.56.\times 7.79\times 298}{10\times 2.36}\\\\T_2=546.91~K=273.91^oC[/tex]
