A consumer group is investigating the number of flights at a certain airline that are overbooked. They conducted a simulation to estimate the probability of overbooked flights in the next 5 flights. The results of 1,000 trials are shown in the following histogram.

Respuesta :

Answer:

C. 0.446

Step-by-step explanation:

1-(0.114+0.332) = 0.446

The sum of the relative frequencies of the bars for 4 and 5 is 0.446.

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The probability that atleast four of the next five flights will be overbooked is the sum of the probabilities of having 4 or 5 flights overbooked which is 0.446

The probability of having atleast 4 flights overbooked can be defined as :

P(X ≥ 5) = P(X = 4) + P(X = 5)

From the probability distribution displayed on the histogram :

P(X ≥ 5) = 0.332 + 0.114 = 0.446

Therefore, the probability of having atleast 4 flights overbooked ls 0.446

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