Respuesta :
Answer:
C. 0.446
Step-by-step explanation:
1-(0.114+0.332) = 0.446
The sum of the relative frequencies of the bars for 4 and 5 is 0.446.
The probability that atleast four of the next five flights will be overbooked is the sum of the probabilities of having 4 or 5 flights overbooked which is 0.446
The probability of having atleast 4 flights overbooked can be defined as :
P(X ≥ 5) = P(X = 4) + P(X = 5)
From the probability distribution displayed on the histogram :
P(X ≥ 5) = 0.332 + 0.114 = 0.446
Therefore, the probability of having atleast 4 flights overbooked ls 0.446
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