Answer: Draw a straight line through (0, -4) and (2, -1)
Diagram is below
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Explanation:
The equation is in the form y = mx+b
m = 3/2 = 1.5 is the slope
b = -4 is the y intercept
The y intercept tells us where the graph crosses the y axis. In this case, it happens at (0,b) = (0,-4)
So (0,-4) is one point on the line.
The slope will tell us how to get to another point. Recall that
slope = rise/run
So we see that rise = 3 and run = 2 indicating we'll go up 3 and over to the right 2. Doing that will have you go from (0,-4) to (2,-1)
Therefore, the line will go through the two points (0,-4) and (2,-1) as shown in the diagram below. You can use more points, but two is the minimum number needed to graph a straight line.
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Another way to get points needed to graph this is to plug in various values of x. Let's say we plug in x = 0
y = (3/2)x - 4
y = (3/2)*0 - 4
y = 0 - 4
y = -4
We see that x = 0 leads to y = -4. So (x,y) = (0,-4) is one point on the line.
If we tried x = 2, then,
y = (3/2)x - 4
y = (3/2)*2 - 4
y = 3 - 4
y = -1
Showing (2,-1) is another point on the line. I didn't pick x = 1 since that would have led to a fractional value. It's easier to work with whole numbers in my opinion.
