Answer:
Slope of a line perpendicular to a line = [tex]\frac{1}{6}[/tex]
Step-by-step explanation:
(x₁ , y₁ ) = (3 , -5) & (x₂, y₂) = (1 , 7)
[tex]slope = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\[/tex]
[tex]= \frac{7-[-5]}{1-3}\\\\=\frac{7+5}{1-3}\\\\=\frac{12}{-2}\\\\= - 6[/tex]
Slope of the perpendicular line = [tex]\frac{-1}{m}[/tex]
[tex]= \frac{-1}{-6}\\\\= \frac{1}{6}[/tex]
